The inequality |x| < 3 has the solution −3 < x < 3, and its graph is an open interval on the number line: hollow circles at −3 and +3 with a shaded segment between them. If your problem reads |x| > 3, the graph flips to two rays pointing outward, with the middle unshaded. The number 7 in your prompt is not part of the inequality—it is very likely the question number or a rendering artifact. Read the actual condition from your assignment screen before clicking any graph.

How the absolute-value inequality produces its graph

Absolute value measures distance from zero on the number line, so |x| < 3 literally means "the distance from x to zero is less than 3." That is why the solution set is everything strictly between −3 and +3. The graph is a single connected segment, and the endpoints are open circles because the inequality is strict—x = 3 has distance exactly 3, which is not less than 3. Swap in ≤ and the circles fill in.

The mechanism behind every absolute-value inequality is a two-case split. For |x| < c (with c positive), you write −c < x < c. For |x| > c, you write x < −c or x > c. The word "or" matters: the solution is a union of two separate rays, which is why the graph has two shaded pieces with a gap in the middle. The gap is the set of points too close to zero to satisfy a "greater than" condition.

A useful sanity check: pick a test point in each proposed region and substitute it back in. For |x| < 3, x = 0 works (0 < 3) and x = 5 fails (5 is not less than 3). For |x| > 3, x = 5 works and x = 0 fails. If a graph shades a region containing a failing test point, it is the wrong graph.

The 7 in the keyword is almost certainly not a coefficient or constant. A condition like |x| < 3/7 would give a much narrower interval, roughly −0.43 < x < 0.43, and no standard problem presents it as "3 7" with a space. If your screen genuinely shows a fraction, treat the fraction as c and apply the same rule. The plain-language version: absolute value turns "distance" into "between" for less-than signs and "outside" for greater-than signs.

Reading the graphing platform's click behavior

Online homework systems typically show four to six candidate number-line graphs and ask you to click the correct one. The distractors are generated systematically, and knowing the generator's habits lets you eliminate wrong options in seconds.

Most wrong graphs differ from the correct one in exactly one feature: closed versus open endpoints, shaded inside versus shaded outside, one ray instead of two, or endpoints at the wrong values (for example, at 0 and 3 instead of −3 and 3). Check those four features in that order before clicking. A graph with filled dots at ±3 and shading between them is the classic trap for a strict inequality—it is the ≤ answer, not the < answer.

On many platforms, clicking a graph selects it, and clicking again may submit or toggle. The instruction "click until the correct graph appears" usually means the platform cycles or confirms selection on each click, so pause between clicks and read the highlighted state. If the platform requires a final submit button, do not rely on the click alone to register your answer.

Quantified context: the four core cases at a glance

The table below reconciles the standard cases and their graphs. The pattern generalizes to any positive constant c; the numbers here use c = 3 to match your problem.

Inequality Solution set Graph shape Endpoints at ±3 Shaded region
|x| < 3 −3 < x < 3 One segment Open circles Between the points
|x| ≤ 3 −3 ≤ x ≤ 3 One segment Closed circles Between the points
|x| > 3 x < −3 or x > 3 Two rays Open circles Outside the points
|x| ≥ 3 x ≤ −3 or x ≥ 3 Two rays Closed circles Outside the points
|x − 2| < 3 −1 < x < 5 One segment Open circles Between −1 and 5
|x + 1| ≤ 3 −4 ≤ x ≤ 2 One segment Closed circles Between −4 and 2

The last two rows matter because most real problems are not centered at zero. When the expression is |x − h| < c, the interval is centered at x = h, so the endpoints are h − c and h + c. For |x − 2| < 3, that is 2 − 3 = −1 and 2 + 3 = 5. Students who graph centered intervals as if they were centered at zero pick the graph with endpoints at ±3, which is one of the standard distractors.

The ≤ versus < distinction is worth 1 point on most rubrics and is the single most common wrong click. Roughly speaking, half the distractor set in typical homework banks is built from endpoint-style errors, so verifying open versus closed circles is the highest-yield check you can perform.

Edge cases the thin explainers skip

Negative constants change everything, and this is where many students misclick even when they understand the basic rule. The absolute value of any real number is never negative, so |x| < −3 has no solution at all—the graph is an empty number line with nothing shaded. Conversely, |x| > −3 is true for every real number, so the graph shades the entire line. These two cases are the professional caveat of this topic: the rule "flip the sign and split" silently breaks when c is negative, and a graph that shades nothing or everything may be the correct answer. For c = 0, |x| < 0 has no solution and |x| ≤ 0 has exactly one solution, x = 0, graphed as a single closed dot.

Compound and nested conditions also appear. A problem like |x| < 3 and x > 0 asks for the intersection of two sets, which is 0 < x < 3—a segment with one open circle at 0 and one at 3. A problem like |x| > 3 or x > 2 asks for a union, and the union of the two rays with (2, ∞) is just x < −3 or x > −3's ray overlap, which simplifies to all reals except exactly −3. Graph-reading questions rarely go this deep, but competition and test-prep sets do.

Red-flag warnings before you click:

A graph with shading between endpoints at 0 and 3 rather than −3 and 3—the left endpoint is wrong. Filled circles on a strict inequality—the boundary point does not satisfy the condition. A single ray for a greater-than inequality—there must be two separate shaded pieces. An empty or fully shaded line without checking whether c is negative first. A graph whose shaded region contains a test point that fails the inequality.

Misconceptions that produce wrong clicks

The biggest misconception is treating the absolute-value bars as parentheses. |x| < 3 is not the same as x < 3; it is the conjunction −3 < x < 3. Students who drop the bars click the graph of a simple "less than 3" ray, which shades everything left of 3. That graph is wrong because it includes x = −10, and |−10| = 10, which is not less than 3.

A second misconception is that the "greater than" graph shades between the endpoints because the inequality "looks bigger." In fact, greater-than absolute-value conditions describe points far from zero, so the shading moves to the outside. The counterintuitive detail is that |x| > 3 excludes a finite interval around zero—the middle gets erased rather than filled. This reversal is why students who memorize one picture get the other one wrong.

A third error is forgetting that the solution set is a set of real numbers, not just integers. The graph shades a continuous interval, so any graph that plots only discrete dots at integer values is the wrong representation for an inequality.

Practical actions: verifying your click in under a minute

Use this fixed routine for any graph-selection question on absolute-value inequalities.

Rewrite the inequality in plain words: "distance from x to zero is less than 3." Identify c and its sign. If c is negative, decide immediately between no solution and all reals. Locate the boundary points at −c and +c (or h − c and h + c if centered). Decide open versus closed from strict versus inclusive symbols. Decide inside shading (less-than) versus outside shading (greater-than). Test one point inside and one outside the proposed shaded region against the original inequality.

That six-step check takes under a minute and catches every standard distractor. If you have time, substitute x = 0 and x = 10 into the original condition as a double check—one should satisfy the inequality and the other should fail for any correct graph of |x| < 3.

The timeline table below maps how the solution routine unfolds across a typical homework attempt, which helps you budget clicks and checks.

Stage What you do Time Common failure here
Reading the prompt Identify the actual inequality 10–20 s Assuming "3 7" is one number
Case analysis Determine c's sign and the case 20–30 s Skipping the negative-c check
Boundary math Compute −c and +c 10–20 s Forgetting the minus sign
Endpoint style Open or closed circles 5–10 s Filled dots on strict inequality
Region choice Inside versus outside 10–20 s Shading the middle for >
Verification Substitute test points 15–30 s Clicking before testing

Limits and what this guide cannot tell you

The specific platform in your assignment controls the exact clicking behavior, and this article cannot know whether your system auto-submits, requires a separate confirmation, or randomizes graph order. Follow your platform's instructions. The mathematical content here is stable and applies to any absolute-value inequality with a single variable, but multi-variable absolute-value inequalities (in two dimensions) produce regions bounded by lines or curves, not number-line graphs. If your problem includes a y-variable, the graph is a plane region and the rules differ.

This article is general educational information about solving and graphing absolute-value inequalities, not a diagnosis, legal opinion, or investment recommendation. It does not replace your instructor's rubric or a qualified tutor's feedback on a specific assignment.